Created at: 2025-05-11
A nonzero integer a is said to divide an integer b if b/a = k for some
integer k.
When a divides b, we write a | b.
When a does not divide b, we write a † b.
a and b be integers.c | a and c | b then c is a common divisor of a and b.a and b is the largest integer d such
that,d | a and d | b.This number (d) is denoted gcd(a,b).
If a and b are non-zero, then
Since 1 | x is true for every integer, then
1 | a and 1 | b are also true, then
The integer 1 is always a common divisor, then
The greatest common divisor will therefore at least be 1.
The greatest common divisor can never be larger than |a| or |b|, then
1 ≤ gcd(a,b) ≤ |a|, and
1 ≤ gcd(a,b) ≤ |b|, and therefore
gcd(a, b) always exists.
When a = 0 and b = 0, then there's no greatest common divisor as every integer is a divisor of 0.
If a and b are positive integers, then there exist integers k and l
such that: gcd(a, b) = ak + bl.
gcd(12,20) = 4
gcd(12,20) = 12k + 20l
gcd(12,20) = 12*2 + 20*-1
k = 2, l = -1
gcd(12,20) = 4
gcd(12,20) = 12k + 20l
gcd(12,20) = 12*-3 + 20*2
k = -3, l = 2
In fact there are infinite solutions. But only one suffices for the theorem.