Created at: 2025-01-27
Say you want the resistance of 5k in parallel with 10k. This is the equivalent of three 10k resistors in parallel. Or one 3.3k (10k/3) resistor
Show that it is not possible to exceed the power rating of a 1/4 watt
resistor of resistance greater than 1k, no matter how you connect it, in a
circuit operating from a 15 volt battery.
From the power formulas:
P = IV
P = I²R
P = V²/R
Say you connect the resistor in series with the circuit, and the circuit has resistance Rc.
P = V²/R
P = (15²)/(>=1k + Rc)
P = 225/(>=1k + Rc)
The highest power is when >=1k + Rc is at a minimum. Meaning that Rc = 0 and
the resistor is 1k.
P = 225/1000
P = 0.225
P < 1/4
Say you connect the resistor in parallel with the circuit, and the circuit has resistance Rc.
R(parallel) = (R1*R2) / (R1+R2)
R(parallel) = (>=1k*Rc) / (>=1k+Rc)
The larger the value of >=1k, the less current will go through it.
The less power will it dissipate (P = I²R).
The higher R(parallel) is when the circuit is opened (Rc = ∞).
In this case all the current flows throw the 1k resistor.
P = V²/R
P = 225/1000
P = 0.225
P < 1/4